Two dogs pull horizontally on ropes attached to a post; the angle between the ropes is 60.0°. If dog A exe?

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We will use component form: FAx = 270*cos(60) = 135 N FAy = 270*sin(60) = 234 N FBx = 300 N (Given) FBy = 0 N Fx = (135+300) = 435 N Fy = (234+0) = 234 N F = sqrt(435)^2 + (234)^2 = 494 N
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